How to find cut off wavelength3/31/2024 ![]() ![]() ![]() Note: The $X$ - ray tube emits the $X$ - rays at the minimum wavelength called as the cut off wavelength. Hence the above answer is also written as $0.496 A° $. The value of the Planck’s constant that is substituted in the above cut off wavelength calculation is $6.64 \times $īy further simplification of the above equation, Using the formula of the cut off wavelength, The potential difference applied on the $X$ - ray tube, $V = 25\,KV = 25000\,V$ ![]() Where $\lambda $ is the cut off wavelength, $h$ is the Planck constant, $c$ is the speed of the light and $V$ is the accelerating potential and $e$ is the charge of the electron. The formula of the cut off wavelength is given by Hint: Use the formula of the cut of wavelength of the $X$ - ray tube given below and substitute all the constants in the formula and the potential difference in the formula and calculate it to find the cut off wavelength of the $X$ - ray tube. ![]()
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